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IBM Aptitude Questions and Answers For Freshers (2018, 2019 and 2020 Batches)
Number of Questions: 18 Questions
Time Limit: 40 mins
| Topics | Questions asked (Approximately) |
|---|---|
| Ratios and Proportion | 2-4 Questions |
| Simple and Compound Interest | 3-5 Questions |
| Partnership | 2-4 Questions |
| Simplification and Approximation | 5-8 Questions |
| Averages | 2-5 Questions |
| Pipes and Cisterns | 2-3 Questions |
| Percentages | 3-4 Questions |
| Probability | 5-6 Questions |
IBM Aptitude Questions and Answers with Explanation
The higher authorities of IBM are going to recruit most skillful, dynamic and talented candidates. Therefore, by learning IBM Aptitude Questions and Solutions there is a chance to get a job. Because we are listed the sample IBM Questions and Answers with Explanation. However, the Aptitude section is very important in placements. Therefore, competitors can gain knowledge by preparing IBM Aptitude Questions and Answers For Freshers 2019. Which help the applicants in the selection process.
Sample IBM Aptitude Questions and Answers Paper
1. Solve 1781.90÷54.20 + 456.13 – 2345.80 *0.98 = ? * 2
A. 988
B. -876
C. -928
D. -675
E.None of these
Answer – C. -928
Explanation:
Let’s take round figure value, then the simplification is
1782÷54+456-2345*1
= 33+456-2345
= -1856/2 = -928
2. Solve 24.95% of 797.07 ÷ 19.05 = 54.88 – ?
A. 36
B. 47
C. 63
D. 45
E. None of these
Answer – D. 45
Explanation:
25% of 800 ÷ 20 = 25*800/100*20
= 10
55-45 = 10
Therefore, forgetting value as a 10 the number should be ‘ 45 ‘
3. The average expenditure of Sharma for January to June is Rs. 4200 and he spent Rs. 1200 in January and Rs.1500 in July. The average expenditure for the months of February to July is:
A. 4250
B. 4500
C. 3500
D. 2750
E. 3250
Answer – A. 4250
Explanation:
Given
The expenditure between January to June = 4200 * 6 = 25200
The expenditure between February to June = 25200 – 1200 = 24000
Therefore, The expenditure between February to July = 24000 + 1500 = 25500/6 = 4250
4. A jar containing 60litres of the mixture of milk and water. The respective ratio of milk and water in the ratio 7:5. From the jar 12litres of the mixture was taken out and 6 liters of pure milk was added. What is the respective ratio of milk and water after the final operation?
A. 12:17
B. 13:19
C. 9:7
D. 17:10
E. None of these
Answer – D. 17:10
Explanation:
7x+5x = 60
Milk = 35litres, water = 25litres
10litres of mixture taken out
Milk = 35-12(7/12) = 35-7 = 28
Water = 25-12(5/12) = 25-5 = 20
28+6 : 20 = 34:20 = 17:10
Therefore, the ratio of Milk and Water after the final operation is 17:10
5. Two varieties of juice are mixed in the ratio of 4:5. The price of 1st variety juice is Rs.14 per liter while the second variety is Rs.17 per liter. Find the average price of the mixture?
A. Rs.15.03
B. Rs.15.67
C. Rs.16.78
D. Rs.17.43
E. None of these
Answer – B. Rs.15.67
Explanation:
Let we assume x = avg price
x-14/17-x = 5/4
4x-56 = 85-5x
5x+4x = 85+56 = 141
9x = 141
x = 141/9 = 15.67
Hence, The average price of the mixture is Rs.15.67
6. Venkat lends Rs 30,000 of two of his friends. He gives Rs 15,000 to the first at 6% p.a. simple interest. He wants to make a profit of 10% on the whole. The simple interest rate at which he should lend the remaining sum of money to the second friend is
A. 16%
B. 12%
C. 14%
D. 8%
E. None of the Above
Answer – C. 14%
Explanation:
The Simple Intrest on Rs 15000
=(15000×6×1)/100 = Rs. 900
Profit to made on Rs 30000
= 30000×10/100=Rs 3000
S.I.on Rs.15000 = 3000-900 = Rs.2100
Rate=(S.I.* 100)/(P * T)=(2100×100)/15000
=14% per annum
Therefore, the simple interest rate at which he should lend the remaining sum of money to the second friend is 14%.
7. Mahesh lends 40% of his money at 15% per annum, 50% of the rest at 10% per annum and the rest at 18% per annum rate of interest. What would be the annual rate of interest, if the interest is calculated on the whole sum?
A. 14.4%
B. 16.5%
C. 18.5%
D. 19.5%
E. None of the Above
Answer – A. 14.4%
Explanation:
x – (40/100)*x = 60x/100
40/100 at 15% p.a = 40/100 * 15/100 = 60x/1000
50/100*60x/100 = 30x/100 at 10% p.a = 30x/100 * 10/100 = 30x/1000
Balance amount = x – 40x/100 – 30x/100 = 30x/100 at 18% p.a = 18/100 * 30x/100 = 54x/1000
R = [(144x/1000)/x] * 100 = 14.4%
Therefore, the annual rate of interst is 14.4%.
8. Find the 4-digit smallest number which when divided by 12, 15, 25, 30 leaves no remainder?
A. 1800
B. 1020
C. 1120
D. 1200
E. None of these
Answer – D. 1200
Explanation:
LCM of 12, 15, 25 and 30 is 300
the least number of 4-digit divided by 300 is 1200
9. A, B, and C can alone complete a work in 10, 12 and 15 days respectively. All started the work but B left the work 3 days before completion. How much work was then done by A and B together in the total work?
A. 2/3
B. 3/4
C. 1/3
D. 3/5
E. 2/5
Answer – A. 2/3
Explanation:
Let us assume that work completed in x days
According to given data A and C worked for all x days and B for (x-3) days. So
(1/10 + 1/15)*x + (1/12)*(x-3) = 1
Solve, x = 5 days
In 5 days, A did 5/10 = 1/2 of work
In (5-3) = 2 days, B did 2/12 = 1/6 of work
So total by A and B = (1/2 + 1/6) = 2/3
Therefore, the total work done by A and B together is 2/3.
10. A sum of money is to be distributed among A, B, C, D in the proportion of 5: 2: 4 : 3. If C gets Rs. 1000 more than D, what is B’s share?
A. Rs. 500
B. Rs. 1500
C. Rs. 2000
D. None of these
Answer – C. Rs. 2000
Explanation:
Let we assume that the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.
Then, 4x – 3x = 1000
x = 1000.
B’s share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.
Therefore, the share of the B is Rs. 2000.
11. Three pipes A, B and C can fill a cistern in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 6 hours. The number of hours taken by C alone to fill the cistern is
A. 12 hours
B. 10 hours
C. 18 hours
D. 8 hours
E. None of these
Answer – C. 18 hours
Explanation:
Given that
A+B+C in 1h = 1/6
A+B+C in 2h = 2/6 = 1/3
Remaining = 1-1/3 = 2/3
A+B in 6hrs = 2/3
A+B in 1hr = 2/18
C alone to fill the cistern = 1/6 – 2/18 = 3-2/18 = 1/18
Therefore, the time taken by C alone to fill the cistern was 18 hours.
12. Two pipes A and B can fill a tank in 6 hours and 5 hours respectively. If they are turned on alternatively for 1 hour each, find the time in which the tank is full.
A. 4hrs 30min
B. 5hrs
C. 6hrs 25min
D.5hrs 30min
E. None of these
Answer – D. 5hrs 30min
Explanation:
We assume that pipe A is opened first
Total= 30, A = 30/6 =1/5, B = 30/5 =1/6
In 2 hrs = 5+6 =11
In 4hrs = 22
Remaining = 30-22 =8
1hr Pipe A = 8-5= 3,Remaining B = 3*1/6 = 30min
Therefore, the time taken in order to fill the tank was 5hrs 30min
13. Two pipes P and Q can fill a tank in 20m and 30m respectively. If both the pipes are opened simultaneously, after how much time should Q be closed so that the tank is full in 16 minutes?
A. 12 min
B. 6 min
C. 10 min
D. 7 min
E. None of these
Answer – B. 6 min
Explanation:
X(1/20+1/30) +(16-x)1/20 = 1
5x/60+16-x/20 =1
5x+48-3x/60 =1
2x+48 = 60
2x=12
X=12/2 = 6
Hence it is proved.
14. Veera Reddy sold 10 sarees for a total profit of Rs. 460 and 12 sarees for a total profit of Rs. 144. At what profit per saree should he sell the remaining 20 sarees so that he gets an average profit of Rs. 18 per sarees?
A. Rs 7.10
B. Rs 7.60
C. Rs 7.99
D. Rs 8
Answer – B. Rs 7.60
Explanation:
According to the given data
Total profit required = Rs.(42 x 18) = Rs.756
Profit on 22 sarees = Rs. (460 + 144) = Rs. 604
Profit on 20 sarees = Rs. (756 – 604) = Rs. 152
Average profit on these sarees = Rs.(152/20) = Rs. 7.60.
Hence it is proved.
15. A retailer buys 40 pens at the market price of 36 pens from a wholesaler. If he sells these pens giving a discount of 1%, what is the profit percent?
A. 22%
B. 25%
C. 26%
D. 10%
Answer – D. 10%
Explanation:
Let us assume that the market price of each pen is Rs. 1.
Then, C.P. of 40 pens = Rs. 36.
S.P. of 40 pens = 99% of Rs. 40 = Rs. 39.60.
Therefore, the percentage of profit = [3.60/36 x 100]% = 10%.
Hence it is proved.
16. The numerator of a rational number is 4 less than the denominator. If the numerator is increased by 15 and denominator is decreased by 4, we get 6. Find a rational number?
A. 1/5
B. 2/7
C. 3/7
D. 5/9
E. None of these
Answer – C. 3/7
Explanation:
let the fraction is (p-4)/p
now, (p -4 + 15)/(p-4) = 6
we get p = 7
Therefore, fraction = 3/7
17. Two different numbers, when divided by the same divisor, leaves remainder 7 and 9 respectively. When their sum is divided by the same divisor remainder was 4. Find the divisor?
A. 13
B. 14
C. 11
D. 12
E. None of these
Answer – D. 12
Explanation:
Let first number N1 = D*a + 7
and second number N2 = D*b + 9
N1 + N2 = (a+b)*D + 16
Remainder is 4
Therefore, D will be 12
18. When a number is added to 20 percent of the second number, we get 150 percent of the second number. Find the ratio between the first and second number?
A. 13:9
B. 12:10
C. 13:10
D. 17:10
E. None of these
Answer – C. 13:10
Explanation:
a + (20/100)*b = (150/100)*b
a:b = 13:10
Therefore, the ratio between the first and second number is 13:10.
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