Numerical Ability Quiz For IBPS RRB Clerk Prelims Exam

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 Numerical Ability Quiz For IBPS RRB Clerk Prelims Exam: The Institute for Banking Personnel Selection (IBPS) is going to conduct the IBPS Clerk Prelims Exam for all the aspirants who have applied. Numerical Ability is an important subject that will be included in the IBPS RRB Clerk Prelims Exam. In this article, we have shared the IBPS RRB Clerk Prelims Questions and Answers for Numerical Ability, following the exam pattern of 40 questions. To achieve a good score in the IBPS RRB Clerk Prelims Exam, utilize the quiz provided here. Let’s take a look at the IBPS RRB Clerk Numerical Ability Prelims Quiz, which is presented below.

Numerical Ability Quiz For IBPS RRB Clerk Prelims Exam

Directions: Study the following information carefully and answer the questions given beside:

The following table shows the number of employees over the given years. 

Numerical Ability Quiz For IBPS RRB Clerk Prelims 1st Question

1. What is the average number of employees in all the colleges together in the year 2015?

a. 3444
b. 3454
c. 3544
d. 3344
e. None of these

Answer: a

Explanation:
Total number of employees in all the colleges in the year 2015
= 3480 + 3520 + 3390 + 3220 + 3610 = 17220
∴ Average =17220/5=3444=172205=3444
Hence, option A is correct.

2. What is the ratio of the total number of employees of college IIT D over the given years to the total number of employees of college IIT C over the given years?

a. 71 : 69
b. 37 : 38
c. 79 : 71
d. 38 : 37
e. 71 : 74

Answer: e

Explanation:
Total number of employees of college IIT D over the given years
= 1860 + 2160 + 2640 + 3220 + 4320 = 14200
Total number of employees of college IIT C over the given years
= 1930 + 2210 + 2870 + 3390 + 4400 = 14800
∴ Required ratio = 14200 : 14800 = 71 : 74
Hence, option E is correct.

3. What is the difference between the total number of employees from college IIT A and college IIT E over the given period of time?

a. 920
b. 980
c. 820
d. 720
e. 880

Answer: a

Explanation:
Total number of employees of college IIT A over the given years
= 2280 + 2540 + 3100 + 3480 + 4500 = 15900
Total number of employees of college IIT E over the given years
= 2450 + 2970 + 3090 + 3610 + 4700 = 16820
∴ Required difference = 920
Hence, option A is correct.

4. What is the average number of employees from college IIT B in the given duration of time period? 

a. 2960
b. 3180
c. 2840
d. 3164
e. 2516

Answer: d

Explanation:
Total number of employees from college IIT B in the given duration of time
period
= 2190 + 2700 + 3210 + 3520 + 4200 = 15820
∴ Average = 15820/5=3164158205=3164
Hence, option D is correct.

5. What is the total of the number of employees from all the colleges in 2014, 2012 and 2016?

a. 49140
b. 49070
c. 47740
d. 48260
e. 50050

Answer: c

Explanation:
Total number of employees from all the college in 2012 = 2280 + 2190 +
1930 + 1860 + 2450 = 10710

Total number of employees from all the college in 2014 = 3100 + 3210 +
2870 + 2640 + 3090 = 14910
Total number of employees from all the college in 2016 = 4500 + 4200 +
4400 + 4320 + 4700 = 22120
∴ Total number of employees = 10710 + 14910 + 22120 = 47740
Hence, option C is correct.

6. Directions: What value will come in place of question mark (?) in the following questions: (You are not expected to calculate the exact value)

? ÷ 574.98 = 441.03 ÷ ? ÷ 529.08

a. 120
b. 115
c. 125
d. 175
e. 105

Answer: e

Explanation:
? ÷ 574.98 = 441.03 ÷ ? ÷ 529.08
? × ? ≈ 575 × 441 ÷ 529
? × ? = 575 × 441 ÷ 23
?2 = 25 × 441
?2 = 5 × 5 × 21 × 21
? = 105
Hence, option E is correct

7. Directions: What value will come in place of question mark (?) in the following questions: (You are not expected to calculate the exact value)

(3476.074 + 246.93 – 4077.08) ÷ 2.04 = ?2 – 258

a. 12
b. 9
c. 81
d. 27
e. None of these

Answer: b

Explanation:
(3476.074 + 246.93 – 4077.08) ÷ 2.04 = ?2 – 258
≈ (3476 + 247 – 4077) ÷ 2 = ?2-258
(3723 – 4077) ÷ 2 = ?2 – 258
– 354 ÷ 2 = ?2 – 258
– 177 + 258 = ?2
?2 = 81
? = 9
Hence, option b is correct.

8. Directions: What value will come in place of question mark (?) in the following questions: (You are not expected to calculate the exact value)

75.04% of 5200 – 675.97 = ? + 3474

a. 350
b. 475
c. 400
d. 325
e. None of these

Answer: c

Explanation:
75.04% of 5200 – 675.97 = ? + 3474
75 × 52 – 676 = ? + 3474
3900 – 26 – 3474 = ?
? = 400

9. Directions: What value will come in place of question mark (?) in the following questions: (You are not expected to calculate the exact value)

255.95 – 625.15 + 44 = ?^2

a. 8
b. 10
c. 4
d. 12
e. 6

Answer: e

Explanation:
255.95 – 625.15 + 44 = ?
2
256 – 625 + 44 = ?
2
16 – 25 + 44 = ?
2
?
2= 35 ≈ 36
? = 6
Hence, option E is correct.

10. In how many distinguishable ways can letters of the word PRESENT be arranged?

a. 2600
b. 2540
c. 2520
d. 2500
e. None of these

Answer: c

Explanation:
Total arrangements are n! where n is total characters in word.
Hence, 7! are the number of ways but as you can see the letter E is
appeared twice in word.
So, for removal of duplicate we divide 7! by 2!.
= 7! ÷ 2!
= 7 × 6 × 5 × 4 × 3
= 2520

11. Sonika has Rs. 5200 and she gives some money to Suraj at a 8% p.a. on simple interest for 3 years and rest money to Srishty at a 5% p.a on simple interest for 2 years. If Sonika gets Rs. 688 as interest, then find the ratio between the money given to Suraj and Srishty.

a. 20 : 7
b. 3 : 10
c. 5 : 4
d. 4 : 3
e. None of these

Answer: b

Explanation:
Let Sonika gives Rs. X to Suraj and Rs. (5200 – X) to Srishty.
Now, as per the question,
[X × 0.08 × 3] + [(5200 – X) × (0.05 × 2)] = 688

0.24X + 520 – 0.1X = 688
0.14X + 520= 688
x = (688 – 520) ÷ 0.14
x = 168 ÷ 0.14
x = 1200
2nd part = 5200 – 1200 = 4000 Rs.
Reqd ratio = 1200 : 4000 = 3 :10
Hence, option B is correct.

12. In a mixture of Wine and water of 60 Litres, 85% is water. If 8 Litre more wine is added into the mixture, then what will be the new percentage of wine in the new mixture.

a. 25%
b. 30%
c. 75%
d. 33%
e. None of these

Answer: a

Explanation:
In 60 litre mixture
Water = 60 × 85% = 51 litre
Wine = 60 × 15% = 9 litre
After adding 8 litre Wine now,
Water = 51 litre
Wine = 9 + 8 = 17 litre
New mixture = 60 + 8 = 68 litre
According to the question
= (17 ÷ 68) × 100
= 25%
Hence, option A is correct.

Directions: Answer the questions based on the information given below.

The line graph given below shows the number of males and females in four different cities.

Numerical Ability Quiz For IBPS RRB Clerk Prelims 13th Question

13. In city A, the number of males is how much percent of the number of females?

a. 60%
b. 80%
c. 75%
d. 90%
e. None of these

Answer: c

Explanation: 

Numerical Ability Quiz For IBPS RRB Clerk Prelims 13th Question Answer

Required percentage = 600/800 × 100 = 75%
Hence, option c

14. Find the married population of city C, which is 75% of its total population.

a. 1040
b. 1170
c. 1230
d. 1270
e. None of these

Answer: b

Explanation:

Numerical Ability Quiz For IBPS RRB Clerk Prelims 13th Question Answer

Required population = 75% of 1560 = 1170

Hence, option b

15. Find the average of the male population of city B, C and D together.

a. 980
b. 960
c. 950
d. 920
e. None of these

Answer: e

Explanation:

Numerical Ability Quiz For IBPS RRB Clerk Prelims 13th Question Answer

Required average = (1500 + 720 + 600)/3 = 940
Hence, option e

16. Find the ratio of the male population to female population of city B.

a. 5:4
b. 4:3
c. 3:5
d. 6:5
e. None of these

Answer: a

Explanation:

 Numerical Ability Quiz For IBPS RRB Clerk Prelims 13th Question Answer

Required ratio = 1500:1200 = 5:4
Hence, option a.

17. Find the difference between the female population of city C and that of city D.

a. 320
b. 340
c. 360
d. 280
e. 300

Answer: b

Explanation:

Numerical Ability Quiz For IBPS RRB Clerk Prelims 13th Question Answer

Required difference = 840 – 500 = 340

Hence, option b.

Directions: Answer the questions based on the information given below.

There are three shops (P, Q and R), each sold laptop and desktop. The number of laptops sold by P is twice that of the same by Q. Total number of laptops sold by all three shops together is 1500. Number of desktops sold by R is twice the number of laptops sold by same shop. Number of desktops sold by Q is 50% more than that of R. Number of desktops sold by Q is 900. Total number of laptops and desktops together sold by shop P is 1300.

18. Find the ratio of the number of laptops to desktops sold by shop Q.

a. 3:7
b. 1:2
c. 2:3
d. 3:5
e. 4:9

Answer: e

Explanation:
Number of desktops sold by Q = 900
Number of desktops sold by R = 900/1.5 = 600
Number of laptops sold by R = 600/2 = 300
Let the number of laptops sold by Q be ‘x’.
So, x + 2x = 1500 – 300
3x = 1200
x = 400
So, number of laptops sold by Q = 400
Number of laptops sold by P = 800
Number of desktops sold by P = 1300 – 800 = 500

Numerical Ability Quiz For IBPS RRB Clerk Prelims 18th Question

Required ratio = 400:900 = 4:9
Hence, option e.

19. Find the number of laptops sold by shop P.

a. 800
b. 600
c. 700
d. 680
e. None of these

Answer: a

Explanation:
Number of desktops sold by Q = 900
Number of desktops sold by R = 900/1.5 = 600
Number of laptops sold by R = 600/2 = 300
Let the number of laptops sold by Q be ‘x’.
So, x + 2x = 1500 – 300
3x = 1200
x = 400
So, number of laptops sold by Q = 400
Number of laptops sold by P = 800
Number of desktops sold by P = 1300 – 800 = 500

Numerical Ability Quiz For IBPS RRB Clerk Prelims 18th Question

Required number of laptops = 800
Hence, option a.

20. Number of laptops sold by Q is what percent of the number of desktops sold by R.

a. 50%
b. 60%
c. 66.67%
d. 75%
e. 33.33%

Answer: c

Explanation:
Number of desktops sold by Q = 900
Number of desktops sold by R = 900/1.5 = 600
Number of laptops sold by R = 600/2 = 300
Let the number of laptops sold by Q be ‘x’.
So, x + 2x = 1500 – 300
3x = 1200
x = 400
So, number of laptops sold by Q = 400
Number of laptops sold by P = 800
Number of desktops sold by P = 1300 – 800 = 500

Numerical Ability Quiz For IBPS RRB Clerk Prelims 18th Question

Required percentage = 400/600 × 100 = 66.67%
Hence, option c.

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