Problems On Trains Aptitude Questions and Answers | MCQ Problems

2022-01-31

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Problems On Trains Aptitude Questions and Answers | MCQ Problems: Everyone knows that solving the Problems On Trains in aptitude is a very difficult task. Moreover, you have to know about the Problems With Trains Tricks, Formulas. So, to give a clear idea, we have given some simple and easy tricks about solving Problems on Trains Questions and Answers easily. At the bottom of this article, we have arranged the Problems on Trains MCQ Online Test. So, simply take the Online Test and gain a complete grip on Train Problems in Aptitude.

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Table of Contents

Problems On Trains Overview – Aptitude Test

Quiz Name	Problems On Trains
Category	Aptitude
Number of Questions	25
Time	30 Minutes
Exam Type	MCQ (Multiple Choice Questions)

Problems on Trains MCQ Quiz – Practice Here

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1. Train A is in station P in platform no. 4 and train B is in station Q. Distance between the two stations is 3 km. Both the trains are on the same track. Train A starts towards Q and train B towards P. There is a point to change track at a 600-meter distance from station P. Train A changes the track so that train B comes and stops at platform number 4 of station P. Find the distance between the track point to train B when train A crosses the track point. Speed of train A is 72 km/hour and the speed of train B is 36 km/hour?

a) 1422 m
b) 1472 m
c) 2100 m
d) 1596 m
e) 1245 m

Answer: C

Explanation:

To goes 600 m train A takes 600/(72*5/18)=30 sec
So, in 30-sec train B travels 30*36*5/18=300 m
Track point is situated 3000-600=2400 m from station Q.
So, we train A cross-track train B is 2400- 300=2100 m distance from track point.

2. Train A crosses a tree in 17.5 seconds and also crosses a 250m long platform in 30 seconds. If the length of train B is 50 m less than that of A and the speed of train B is 18 kmph more than that of A, then find the time taken by train B crosses a 150m long tunnel.

a) 24 seconds
b) 12 seconds
c) 18 seconds
d) 36 seconds
e) None of these

Answer: C

Explanation:

Length of train A = x
Speed of train A = y
x = y * 5/18 * 17.5
x = 87.5y/18
x + 250 = y * 5/18 * 30
87.5y/18 + 250 = 25y/3
62.5y/6=750
y = 72
x = 350
Length of train B = 350 – 50 = 300 m
Speed of train B = 72 + 18 = 90 kmph
Required time = (300 + 150)/90 * 5/18 = 18 seconds

3. The length of train A is 25% more than that of train B and the speed of train A is 20% more than that of B. If train A crosses a tree in 12 seconds and also crosses train B running in the same direction in 162 seconds, then find the speed of train B.

a) 100 kmph
b) 60 kmph
c) 90 kmph
d) 50 kmph
e) Cannot be determined

Answer: B

Explanation:

Let the length of train B be L and its speed be S.
Then, the length of train A is 1.25L (25% more than that of train B), and its speed is 1.2S (20% more than that of train B).
When train A crosses a tree in 12 seconds, we can use the formula:
distance = speed × time
Let the distance between the tree and the starting point of train A be D. Then, we have:
1.2S × 12 = D
D = 14.4S
When train A crosses train B running in the same direction, we can use the formula:
relative speed = speed of A – speed of B
Let the distance between the two trains be X. Then, we have:
1.2S – S = 0.2S (the relative speed)
X = (1.25L + L) = 2.25L (the relative distance)
So, we have:
time = distance / relative speed
162 = 2.25L / 0.2S
Solving for L, we get:
L = 450 / S
Substituting this value of L in the equation for the relative distance, we get:
X = 2.25 × (450 / S) = 1012.5 / S
Now, we can use the formula for the time taken by train A to cross train B:
time = distance / relative speed
time = X / (1.2S – S) = X / 0.2S
Substituting the values of X and S, we get:
162 = (1012.5 / S) / (0.2S)
Solving for S, we get:
S = 60 kmph
Therefore, the speed of train B is 60 kmph, which is option (b).

4. Train A crosses 200 m long tunnel in 30 seconds and train B also crosses the same tunnel in 18 seconds and the speed of train B is 50% more than the speed of train A. If the difference between the speed of train A and B is 30 kmph, then find the time taken by train A crosses train B running in same direction?

a) 54 seconds
b) 48 seconds
c) 66 seconds
d) 72 seconds
e) 90 seconds

Answer: C

Explanation:

Speed of train A = 2x
Speed of train B = 2x * 150/100 = 3x
3x – 2x = 30x = 30
Speed of train A = 2 * 30 = 60 kmph
Speed of train B = 3 * 30 = 90 kmph
Length of train A=x
Length of train B=y
200 + x=60 * 5/18 * 30
x =300 m y + 200=90 * 5/18 * 18
y =250
Required time = (300 + 250)/30 * 5/18 = 66 seconds

5. The ratio between the speed of a train and a bus is 8:5 respectively. Also, a car covered a distance of 320km in 10hrs. The speed of car is half the speed of the train. Find the speed of bus

a) 40 km/hr
b) 45 km/hr
c) 48 km/hr
d) 58 km/hr
e) 50 km/hr

Answer: A

Explanation:

6. A 240m train A crosses another 300m long train B running in the same direction in 36sec. If the speed of train A be 54km/hr which is lesser than the speed of train B, then what is the speed of second train?

a) 20m/sec
b) 30m/sec
c) 25m/sec
d) 35m/sec
e) 40m/sec

Answer: B

Explanation:

7. Two trains (train A and Train B) of length 150m and 200m respectively with the same speed pass a tree in 6sec and 20sec respectively. In what time they will cross each other if they are moving in opposite directions?

a) 12 sec
b) 11 sec
c) 20 sec
d) 9 sec
e) 10 sec

Answer: E

Explanation:

8. A train crosses a bridge of 400 m in 65 seconds. Speed of train is 36 km/hour. How long it will take to cross a platform of length 350 m?

a) 2 minutes
b) 1 minute
c) 40 second
d) 45 second
e) 50 second

Answer: B

Explanation:

Speed of train = 36 x 5/18 = 10 m/s
In 65 seconds, it will cover = 650 m
Length of train = 650 – 400 = 250 m
Time taken by train to cover platform of 350 m
Distance = 250 + 350 = 600 m
Speed = 10 m/s
∴ Time = 600/ 10 = 60 seconds = 1 minute

9. Train A crosses a platform of length 400 m in 40 sec. Speed of Train A is 20 m/s and length of Train B is two-fifth the length of Train A . Find the length of train B .

a) 160 m
b) 200 m
c) 180 m
d) 220 m
e) 120 m

Answer: A

Explanation:

Train A travel distance in 40 sec = 40 × 20 = 800 m
Length of train A = 800 – 400 = 400 m
Length of Train B = 400 × 2/5 = 160 m

10. A passenger train departs from Chennai at 8pm. for Madurai. At 11 p.m an express train, whose average speed exceeds that of the passenger train by 15 km/hr, leaves Madurai for Chennai. Two trains meet each other mid-route. At what time do they meet, given that the distance between the cities is 1080 km?

a) 8 a.m
b) 8:30 p.m
c) 12 mid-nigh
d) 4 a.m
e) None of these

Answer: A

Explanation:

Let speed of passenger train = x
Speed of express train = x +15
Let they meet after t hour
So distance travelled by both is same = 1080/2 = 540
Distance travelled by passenger train = x(t+3)
Distance travelled by express train = (x + 15)t
=> x(t+3) = (x + 15)t
x = 5t
Total distance = 1080
x(t+3) + (x + 15)t = 1080
t2+ 3t-108 = 0
(t-9)*(t+12)=0
so t = 9, – 12 (-12 hrs not acceptable time can’t be negative)
They meet after 9 hours
Time = 11:00 pm+ 9 hours = 8:00 am

11. Q. The distance between two stations A and B is 800 km. A train x starts from A and moves towards B at 40km/h and another train Y starts from B and moves towards A at 60km/h. How far from A will they cross each other?

a) 380 km
b) 320 km
c) 300 km
d) 360 km
e) None

Answer: B

Explanation:

12. A train leaves a station A at 7 am and reaches another station B at 11 am. Another train leaves B to 8 am and reaches A at 11:30 am. The two trains cross one another at

a) 8:36 AM
b) 8:56 AM
c) 9:00 AM
d) 9:24 AM
e) None

Answer: D

Explanation:

Kindly refer to the video or go through the explanation given below :
Let the distance between the stations A & B be 4 kms.
∴ Speed A → B = 4/4=1 km/hr
& Speed B → A = 4/(7/2)=8/7km/hr
Suppose they meet x hours after 8 am.
Distance covered by both the trains to meet each other = Distance covered by them from 8 am
(1+8/7)*x=3kms
=15/7 x=3
∴ They will meet at 9 : 24 AM. (After adding 1 hr 24 mins to 8 am.)
Hence, option D is correct.

13. If a train runs with the speed of 84 km/hr, it reaches its destination late by 25 minutes. However, if its speed is 98 km/hr, it is late by 10 minutes only. The right time for the train to cover its journey is –

a) 60 minutes
b) 80 minutes
c) 75 minutes
d) 92 minutes
e) None

Answer: B

Explanation:

Let t be the right time
84(t + 25) = 98(t + 10)
6(t + 25) = 7(t + 10)
150 – 70 = t
t = 80 min

14. A 720m long train takes 96 seconds more to cross a platform than it takes to cross a pole at the same speed. Given that the length of platform is twice the length of train. What is the speed of train in km/h ?

a) 36
b) 54
c) 45.5
d) 64.4
e) None

Answer: B

Explanation:

15. A train starts at 11:00 am from point A towards point B at 36 km /h while a car starts at 1:00 pm from point B towards point A at 44 km/h. They cover a distance of 712 km till the meeting. At what time will they meet each other?

a) 7:30 pm
b) 8:00 pm
c) 8:30 pm
d) 9:00 pm
e) None

Answer: D

Explanation:

16. The distance between Navi Mumbai and Kolhapur is 330km on a straight line. ‘Koyna Express’ starts from Mumbai at exactly 9 pm towards Kolhapur with a speed of 60km/hr. While, ‘Mahalaxmi express’ starts from Kolhapur at exactly 10 pm towards Mumbai with a speed of 75 km/hr. At what time do these two trains will meet during their travel?

a) 1:00am
b) 10.20 pm
c) 12.30 am
d) 12 midnight
e) None

Answer: D

Explanation:
⇒Suppose Koyna Express and Mahalaxmi express meet each other ‘a’ hours after 9 pm.
⇒Distance covered by Koyna Express in ‘a’ hours = 60a km
⇒Distance covered by Mahalaxmi Express in (a – 1) hrs = 75 (a – 1) km
⇒60a + 75 (a – 1) = 330
⇒60a + 75a -75 =330
⇒135a = 405
⇒a = 3
⇒Two trains will meet after 3 hours of 9 pm .ie. 12 midnight

17. A man in a train notices that he can count 96 electric posts in one minute. If they are known to be 60 m apart, then what is the speed of the train?

a) 96km/h
b) 342m/s
c) 95km/h
d) 342km/h
e) None

Answer: B

Explanation:

18. Two trains running in opposite directions on parallel tracks, at speeds of 33 km/hr and 39 km/hr, take 23 seconds to cross each other. If the length of one train is 250 m, then the length of the other train is:

a) 210 m
b) 225 m
c) 240 m
d) 190 m
e) None

Answer: A

Explanation:

19. Two trains running in opposite directions on parallel tracks, at speeds of 37 km/hr and 44 km/hr, take 24 seconds to cross each other. If the length of one train is 265 m, then the length of the other train is:

a) 210 m
b) 225 m
c) 275 m
d) 250 m
e) None

Answer: C

Explanation:

20. Aman’s speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man’s speed against the current is :

a) 9.5 km/hr
b) 10 km/hr
c) 10.5 km/hr
d) 11 km/hr
e) None

Answer: B

Explanation:

Man’s rate in still water = (15 – 2.5) km/hr = 12.5 km/hr.
Therefore, Man’s rate against the current = (12.5 – 2.5) = 10 km/hr.

21. A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is ?

a) 45 kmph
b) 25 kmph
c) 30 kmph
d) 50 kmph
e) None

Answer: D

Explanation:

Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec.
[(25/2) x (18/5)] km/hr = 45 km/hr.
Let the speed of the train be ‘S’ km/hr.
Then, relative speed = (S – 5) km/hr.
S – 5 = 45 => S = 50 km/hr.

22. A train 150 m long passes a pole in 15 seconds and crosses another train of the same length travelling in opposite direction in 8 seconds. The speed of the second train in (km/h) is

a) 60 km/hr
b) 66 km/hr
c) 72 km/hr
d) 99 km/hr
e) None

Answer: D

Explanation:

Speed of the first train = 150/50=10 m/sec
Let the speed of the second train be x m/sec
Relative speed = (10 + x)m/sec
Length of train 1 + length of train 2 = 150 + 150 = 300 mtr
In the second scenario equation will be like 300/10+x=8
or, 300 = 80 + 8x
or, x = 220/8=55/2m/sec
∴ speed of the second train = 55/2*18/5=99km/hr
Hence, option D is correct.

23. A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?

a) 230 m
b) 240 m
c) 260 m
d) 270 m
e) None

Answer: D

Explanation:

Speed =[ 72 x (5/18) ]m/sec= 20 m/sec.
Time = 26 sec.
Let the length of the train be x metres.
Then,[ (x+250)/26 ]= 20
=> x + 250 = 520
=> x = 270.

24. Two stations P and Q are 110 km apart on a straight track. One train starts from P at 7 a.m. and travels towards Q at 20 kmph. Another train starts from Q at 8 a.m. and travels towards P at a speed of 25 kmph. At what time will they meet?

a) 10.30
b) 10
c) 8.45
d) 9.30
e) None

Answer: B

Explanation:

Assume both trains meet after x hours after 7 am
Distance covered by train starting from P in x hours = 20x km
Distance covered by train starting from Q in (x-1) hours = 25(x-1)
Total distance = 110
=> 20x + 25(x-1) = 110
=> 45x = 135
=> x= 3
Means, they meet after 3 hours after 7 am, ie, they meet at 10 am

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Problems on Trains Aptitude Questions and Answers

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Problems On Trains Aptitude Questions and Answers | MCQ Problems

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